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Game Development Ue Containers Strings Memory Interview Questions

75 verified Game Development Ue Containers Strings Memory interview questions — solve with answers, learn from explanations, test yourself in a real simulation.

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Sample questions

Ue Containers Strings MemoryDifficulty 1
What happens when a TArray needs to grow beyond its current allocated capacity during an Add() call?
  • aAdd() throws an exception and the new element is discarded.
  • bIt reallocates to a bigger block and moves the elements.
  • cAdd() does nothing and silently returns false.
  • dThe oldest element is dropped to make room for the new one.
Explanation:When there is no spare capacity, TArray reallocates: it requests a bigger memory block, transfers the current elements into it, releases the old block, and only then adds the new element.
Ue Containers Strings MemoryDifficulty 2
If you insert five key-value pairs into a TMap in a specific order, then remove one and iterate the map with a range-based for loop, what can you say about the iteration order?
  • aIt always matches insertion order, exactly like a sorted associative container.
  • bIt always matches insertion order until an element is removed, then reverses.
  • cIt is sorted by the hash of the key, in strictly ascending order.
  • dIt is not guaranteed to match insertion order and can change after removals.
Explanation:TMap stores entries in an internal sparse array indexed by hash; it does not preserve insertion order, and removing elements can further reorder how existing entries are visited during iteration.
Ue Containers Strings MemoryDifficulty 2
Why shouldn't you wrap a UObject-derived pointer in a TSharedPtr?
  • aUObject already has its own lifetime tracking, and the two systems don't know about each other.
  • bTSharedPtr can only hold value types, not pointers to classes.
  • cUObject-derived classes forbid inheriting from any templated base at compile time.
  • dTSharedPtr always runs its reference counting on the render thread, corrupting UObjects.
Explanation:UObjects are tracked by Unreal's own garbage collector, which is completely separate from TSharedPtr's independent reference counting; mixing the two leaves neither system aware of the other's references.
Ue Containers Strings MemoryDifficulty 1
What is FName primarily designed for in Unreal Engine?
  • aBuilding and mutating long blocks of user-facing paragraph text.
  • bStoring localized text that changes with the player's selected language.
  • cFast, case-insensitive identifiers such as socket names or tags.
  • dFormatting numbers and dates for display in the UI.
Explanation:FName represents a name stored in a shared, deduplicated table; it's meant for lightweight identifiers you compare or look up often, not for text you display or mutate.
Ue Containers Strings MemoryDifficulty 2
Why is passing a large TArray<FVector> into a function by const TArray<FVector>& preferable to passing it by value?
  • aBy-value parameters are always passed as raw pointers internally, so there is no real difference.
  • bPassing by value copies the entire array; the const reference avoids that copy.
  • cconst references make the array elements mutable inside the function, unlike by-value.
  • dBy value passing moves the array, leaving the caller's array empty afterward.
Explanation:TArray's copy constructor performs a deep copy of every element. Binding a const reference parameter avoids that allocation and copy entirely, since no new array is created.
Ue Containers Strings MemoryDifficulty 3
TArray<FVector> Points;
Points.Reserve(2);
Points.Add(FVector::ZeroVector);
FVector* First = &Points[0];
Points.Add(FVector::UpVector);
Points.Add(FVector::ForwardVector);
First->X = 5.0f;

What is true about the line First->X = 5.0f;?
  • aIt is undefined behavior: the third Add() may reallocate, leaving First pointing at freed memory.
  • bIt safely modifies Points[0].X, since Reserve(2) guarantees the array never reallocates again.
  • cIt compiles but is a no-op, because TArray elements cannot be modified through a raw pointer.
  • dIt always modifies Points[1].X instead, since the array shifted after the first Add().
Explanation:Reserve(2) only guarantees capacity for 2 elements. After two Adds, the array is full; the third Add() (a total of 3 elements) forces a reallocation, invalidating First and making the dereference undefined behavior.

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